18a^2-41a-10=0

Solution for 18a^2-41a-10=0 equation:

18a^2-41a-10=0

a = 18; b = -41; c = -10;
Δ = b2-4ac
Δ = -412-4·18·(-10)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-49}{2*18}=\frac{-8}{36}
=-2/9
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+49}{2*18}=\frac{90}{36}
=2+1/2
$